(x+5)(x-3)(x^2+1)=0

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Solution for (x+5)(x-3)(x^2+1)=0 equation:


Simplifying
(x + 5)(x + -3)(x2 + 1) = 0

Reorder the terms:
(5 + x)(x + -3)(x2 + 1) = 0

Reorder the terms:
(5 + x)(-3 + x)(x2 + 1) = 0

Reorder the terms:
(5 + x)(-3 + x)(1 + x2) = 0

Multiply (5 + x) * (-3 + x)
(5(-3 + x) + x(-3 + x))(1 + x2) = 0
((-3 * 5 + x * 5) + x(-3 + x))(1 + x2) = 0
((-15 + 5x) + x(-3 + x))(1 + x2) = 0
(-15 + 5x + (-3 * x + x * x))(1 + x2) = 0
(-15 + 5x + (-3x + x2))(1 + x2) = 0

Combine like terms: 5x + -3x = 2x
(-15 + 2x + x2)(1 + x2) = 0

Multiply (-15 + 2x + x2) * (1 + x2)
(-15(1 + x2) + 2x * (1 + x2) + x2(1 + x2)) = 0
((1 * -15 + x2 * -15) + 2x * (1 + x2) + x2(1 + x2)) = 0
((-15 + -15x2) + 2x * (1 + x2) + x2(1 + x2)) = 0
(-15 + -15x2 + (1 * 2x + x2 * 2x) + x2(1 + x2)) = 0
(-15 + -15x2 + (2x + 2x3) + x2(1 + x2)) = 0
(-15 + -15x2 + 2x + 2x3 + (1 * x2 + x2 * x2)) = 0
(-15 + -15x2 + 2x + 2x3 + (1x2 + x4)) = 0

Reorder the terms:
(-15 + 2x + -15x2 + 1x2 + 2x3 + x4) = 0

Combine like terms: -15x2 + 1x2 = -14x2
(-15 + 2x + -14x2 + 2x3 + x4) = 0

Solving
-15 + 2x + -14x2 + 2x3 + x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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